# NCERT Solutions for Class 10 Maths Chapter 8 Exercise 8.3

Free download NCERT Solutions for Class 10 Maths Chapter 8 Exercise 8.3 introduction to trigonometry (Trigonometric functions and their applications in simple situations) in English Medium and Hindi Medium PDF form to free download. Download Exercise 8.1 or  Exercise 8.2 or Exercise 8.4 also in PDF form to use it offline or continue using online study.

## NCERT Solutions for Class 10 Maths Chapter 8 Exercise 8.3

If you need solutions in Hindi, Click for Hindi Medium solutions of 10 Maths Exercise 8.3

Exercise 8.1

Exercise 8.2

Exercise 8.4

10 Maths Main Page

### Class 10 Maths Exercise 8.3 Solutions in Hindi Medium

Exercise 8.1

Exercise 8.2

Exercise 8.4

10 Maths Main Page

To get the solutions in English, Click for English Medium solutions.

##### Trigonometry – Important Questions for Practice
###### Selected from CBSE Board Papers

Question 1: Evaluate: [tan²45⁰] / [sin²45⁰ + cos²45⁰] [Answer: 105⁰]

Question 2: Evaluate: [4 cot²60⁰ + sec²30⁰ – 2sin²45⁰] / [sin²60⁰ + cos²45⁰]. [Answer: 4/3]

Question 3: Simplify: (1/[cos θ] + [sin θ]/[cos θ]) ([1 – sin θ]/[cos θ]) [Answer: 1]

Question 4: Prove that (tan θ +2) (2 tan θ + 1) = 5 tan θ + 2sec²θ.

Question 5: Prove that (cosec θ – sin θ) (sec θ – cos θ) = cos θ sin θ.

Question 6: Prove that 2 sec²θ – sec4 θ – 2 cosec² θ + cosec4 θ = cot4 θ – tan4 θ.

Question 7: Prove that [cos³θ + sin³θ] / [cos θ + sin θ] + [cos³θ – sin³θ] / [cos θ – sin θ] = 2.

Question 8: Prove that [sec θ + tan θ] / [sec θ – tan θ] = ([1 + sin θ] / cos θ)².

Question 9: Prove that [1 + cos A] / [sin A] + [sin A] / [1 + cos A] = 2 cosec A.

Question 10: Prove that cot4 A – 1 = cosec4 A – 2 cosec²A.

Question 11: Show that [1 + cos θ – sin2 θ] / [sin θ (1 + cos θ)] = cot θ.

Question 12: Prove that [sin A] / [sec A + tan A – 1] + [cot A] / [cosec A + cot A – 1] = 1.

Question 13: Prove that sin A (1 + tan A) + cos A (+ cot A) = sec A + cosec A.

Question 14: Prove that sec4 θ – tan4 θ = 1 + 2 tan²θ.

Question 15: Prove that [cosec A] / [cosec A – 1] + [cosec A] / [cosec A + 1] = 2 sec²A.

Question 16: Prove that [cot θ] / [cosec θ + 1] + [cosec θ + 1] / [cot θ] = 2 sec θ.

NCERT Solutions for Class 10 Maths Chapter 8 Exercise 8.3 includes the questions based on complementary angles of sin, cos, tan, sec, cosec and cot. As per Syllabus of class 10 for 2018-19, only the values of trigonometric ratios less than or equal to 90 will be asked in the examination.